Compare Version Numbers (Easy)

Description:

Compare two version numbers version1 and version2.
If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0.
You may assume that the version strings are non-empty and contain only digits and the . character.
The . character does not represent a decimal point and is used to separate number sequences.
For instance, 2.5 is not “two and a half” or “half way to version three”, it is the fifth second-level revision of the second first-level revision.

Analysis

比较数的大小，将字符串进行分割后一一比较就好了～

My Solution

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//C++
class Solution {

private:
    vector<int> splite(string s){
        vector<int> ans;
        ans.clear();
        char c[100];
        int i , j;
        for(i=0,j=0;i<(int)s.length();i++){
            if(s[i]!='.')
                c[j++]=s[i];
            else{
                c[j]=0;
                ans.push_back(atoi(c));
                j = 0;
            }
        }
        if(j!=0){
            c[j]=0;
            ans.push_back(atoi(c));
        }
        return ans;
    }

public:
    int compareVersion(string version1, string version2) {
        vector<int> v1,v2;
        v1 = this->splite(version1);
        v2 = this->splite(version2);
        int len1 = v1.size();
        int len2 = v2.size();
        int len = min(len1,len2);
        for(int i=0;i<len;i++){
            if(v1[i]>v2[i])
                return 1;
            if(v1[i]<v2[i])
                return -1;
        }
        for(int i=len;i<len1;i++)
            if(v1[i]!=0)
                return 1;
        for(int i=len;i<len2;i++)
            if(v2[i]!=0)
                return -1;
        return 0;
    }
};