Length of Last Word (Easy)

Description:

Given a string s consists of upper/lower-case alphabets and empty space characters ‘ ‘, return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.

Analysis:

不多说了,水题,查找最后一个单词。可以从后往前找,删除多余空格即可～

My Solution:

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//C++
class Solution {
    public:
    int lengthOfLastWord(const char *s) {
        int i = strlen(s)-1 ,num=0;
        while(i>=0&&s[i]==' ')
            i--;
        while(s[i]!=' '&&i-->=0)
            num++;
        return num;
    }
};