Reverse Integer (Easy)

Description

Reverse digits of an integer.

Example1: x = 123, return 321
Example2: x = -123, return -321

Analysis

翻转数字。问题在于翻转之后的数字可能越界。如果越界则返回0.
我的方法比较笨= =。翻转两次判断答案和原来的x是否相等。特判10的倍数。

My Solution

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//C++
class Solution {
public:
    int reverse(int x) {
        int flag = 1,y = 0 ,z = 0,tx,ty;
        if(x<0){
            flag = -1;
            x = -x;
        }
        tx = x;
        while(x){
            y = y*10+x%10;
            x/=10;
        }
        ty = y;
        while(y){
            z = z*10+y%10;
            y/=10;
        }
        if(z==tx||tx%10==0)
            return flag*ty;
        else
            return 0;
    }
};